The solution is x = 8 and y = 2
Solution:
Given are the system of equations
2x + 3y = 22 -------- eqn 1
-2x + 5y = -6 ----- eqn 2
We can solve the system of equations by elimination method
Add eqn 1 and eqn 2
Eqn 1 + Eqn 2
2x + 3y -2x + 5y = 22 - 6
0x + 3y + 5y = 16
8y = 16
Divide both sides of equation by 8
Substitute y = 2 in eqn 1
2x + 3(2) = 22
2x = 22 - 6
2x = 16
Thus the solution is x = 8 and y = 2
