Question

Find DC

HELP PLEASE!! :(
using sine cosine or tangent

Answer 1

DC=14

Explanation

consider triangle ADB

<BAD=54°

sin<BAD=opposite side/ hypotenuse

sin 54°=BD/BA

BD=BA sin 54°=20*0.8=16

consider triangle BDC

cos <BCD=adjacent side/hypotenuse

=DC/BC

cos 28°=DC/BC

DC=cos28°  *BC

=0.88*16=14.08