Question

How much work would it take to push two protons very slowly from a separation of 2.00×10−10m (a typical atomic distance) to 3.00×10−15m (a typical nuclear distance)?

Answer 1

Answer: 7.68×10^14 J

Explanation:

The magnitude of the charge q1=q2 = 1.6×10^-19 C

Proportionality constant K = 9×10^9 Nm²/C²

Da= 2×10^-10m

Db= 3 ×10^-15m

W= k q1q2 ( 1/Db -1/Da)

W= 9×10^9 (1.69×10^-19)²(1/3.0×10^-15 - 1/2×10^-10)

W= 7.68 ×10^-14J

Therefore the amount of work requires is 7.68 ×10^-14J