Question

A laser is thrown upward with a speed of 12 m/s on the surface of planet X where the acceleration due to gravity is 1.5 m/s2 and there is no atmosphere. What is the maximum height reached by the laser?

Answer 1

Answer:

48 m

Explanation:

Initial speed of laser,u=12 m/s

Acceleration due to gravity=-$1.5m/s^2$

Because laser goes against to gravity when it is thrown in upward direction.

Final velocity of laser=v=0

We know that

$v^2-u^2=2as$

Substitute the values then we get

$0-(12)^2=2(-1.5)s$

$-144=-3s$

$s=\frac{144}{3}$

$s=48 m$

Hence, the maximum height reached by the laser= 48 m

Answer 2

The maximum height reachedby the laser is 48 m.

To calculate the maximu height reached by the laser, we use the formula below.

Formula:

• v² = u²+2gH........... Equation 1

Where:

• u = Initial velocity
• v = final velocity
• g = accceleration due to gravity of planet X
• H = maximum height reached by the laser.

Make H the subject of the equation

• H = (v²-u²)/2g........... Equation 2

From the question,

Given:

• v = 12 m/s
• u = 0 m/s
• g = 1.5 m/s²

Substitute these values into equation 2

• H = (12²-0²)/(2×1.5)
• H = 144/3
• H = 48 m

Hence, The maximum height reachedby the laser is 48 m.

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