Question

Find the force exerted by the surface on the point of contact with the hammer head. Assume that the force the hammer exerts on the nail is parallel to the nail.

Answer 1

Answer:

716.3N

Step-by-step explanation:

Moment produced by force F = 150 N:

Mf = 150 * 30 = 4500 Ncm

The same moment is imparted at the nail.

Fn * 5 / sin (60) = 4500 Ncm

Fn = 779.423 N

Force exerted by surface on hammer pivot is:

Fx = 779.423 sin (30) - 150 = 239.7115 N

Fy = 779.423 cos (30) = 675 N

Fres = sqrt ( (Fx)^2 + (Fy)^2)

Fres = sqrt ( 675 ^2 + 239.7115^2)

Fres = 716.3 N

Answer 2

The force the hammer exerts on the nail is parallel to the nail. is 716.3 N

Force and moment

From the given information, we ned to first calculate the moment as shown:

• Moment produced by force F = 150 N:

Since Moment = Force * distance:

• Mf = 150 * 30 = 4500 Ncm

The same moment is imparted at the nail.

5Fn/sin (60) = 4500 Ncm

Fn = 779.42N

Next is to calculate the force exerted by the surface on the hammer pivot.

Fx = 779.423 sin (30) - 150 = 239.7115 N

Fy = 779.423 cos (30) = 675 N

$F = \sqrt{ ( (Fx)^2 + (Fy)^2)}\\F = \sqrt{ ( 675 ^2 + 239.7115^2)}\\F = 716.3N$

The force the hammer exerts on the nail is parallel to the nail. is 716.3 N

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