Question

Respond to the following based on your reading.
m
1. What amount of work is done when a force of 50 N is used to drag an object a distance of 20
meters across a floor?
i
2. What's the kinetic energy of an object that has a mass of 12 kilograms and moves with a velocity
of 10 m/s?
3. A skateboarder is inside
of a half-pipe, shown here.
Explain her energy
transformations as she
jumps off at point A, slides
to point B, and finally
reaches point c
G
4. If the skateboarder
continues going back and
forth on the half-pipe she'll

Answer 1

1) The work done is 1000 J

2) The kinetic energy is 600 J

3) There is a continuous conversion between kinetic and potential energy

Step-by-step explanation:

1)

The work  done by a force when pushing/pulling an object is given by

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement

$\theta$ is the angle between the direction of the force and of the displacement

In this problem, we have:

F = 50 N is the force

d = 20 m is the displacement

$\theta=0$, assuming the object is parallel to the displacement

Substituitng,

$W=(50)(20)(cos 0)=1000 J$

2)

The kinetic energy of an object is the energy due to the motion of the object. It is given by

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

For the object in this problem,

m = 12 kg is the mass

v = 10 m/s is the speed

Substituting, we find

$K=\frac{1}{2}(12)(10)^2=600 J$

3)

Here the skateboarder is moving on the half-pipe. According to the law of conservation of energy, the total mechanical energy, sum of kinetic and potential energy, is conserved:

$E=KE+PE=const.$

This means that:

• When the skateboarder is at the highest point of its motion, its potential energy PE is maximum, while the kinetic energy KE is zero
• When the skateboarder is at the lowest point of its motion, its potential energy PE is zero, while the kinetic energy KE is maximum

Therefore, there is a continuous conversion between potential and kinetic energy.

Learn more about work and kinetic energy:

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