Answer:
Therefore the length of NO is 18 units.
Step-by-step explanation:
Given:
∆JKL~∆MNO and
[tex]\dfrac{JK}{MN}=\dfrac{2}{3}[/tex]
KL = 12.
To Find :
the length of NO = ?
Solution:
Δ JKL ~ Δ LMN ….{Given)
If two triangles are similar then their sides are in proportion.
[tex]\dfrac{JK}{MN} =\dfrac{KL}{NO}=\dfrac{JL}{MO} \textrm{corresponding sides of similar triangles are in proportion}\\[/tex]
Substituting the values we get
[tex]\dfrac{2}{3} =\dfrac{12}{NO}\\\\NO=\dfrac{36}{2}=18\\\\NO=18\ unit[/tex]
Therefore the length of NO is 18 units.
