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Question:

Marissa walked her dog 1/10 mile on saturday and 55/100 mile on sunday. how far did she walk her dog in all?​

Answer:

Marissa walked [tex]\frac{65}{100}[/tex] miles altogether on saturday and sunday

Solution:

Given that, Marissa walked her dog

From given information,

[tex]\text{Miles walked on saturday } = \frac{1}{10} \text{ mile }\\\\\text{Miles walked on sunday } = \frac{55}{100} \text{ mile }[/tex]

We have to find the distance walked in all

[tex]\text{Total distance } = \text{Miles walked on saturday + Miles walked on sunday }[/tex]

Substituting the values we get,

[tex]\text{Total distance } = \frac{1}{10} + \frac{55}{100}[/tex]

Make the denominators same for easier calculations by taking L.C.M of 10 and 100

Prime factors of 10 = 2 x 2 x 5

Prime factors of 100 = 2 x 2 x 5 x 5

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

The new superset list is

2, 2, 5, 5

Multiply these factors together to find the LCM

LCM = 2 x 2 x 5 x 5 = 100

[tex]\text{Total distance } = \frac{1}{10} + \frac{55}{100}[/tex]

[tex]\text{Total distance } = \frac{1 \times 10}{10 \times 10} + \frac{55}{100}\\\\\text{Total distance } = \frac{10}{100} + \frac{55}{100}\\\\\text{Total distance } = \frac{10+55}{100} = \frac{65}{100}[/tex]

Thus she walked [tex]\frac{65}{100}[/tex] miles altogether on saturday and sunday

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