Respuesta :
Answer:
Option a) Mean
Mean is affected a lot by the change in the last observation as the median remains the same.
Step-by-step explanation:
we are given the following in the question:
Data set A: 64, 65, 66, 68, 70, 71, 72
Data set B: 64, 65, 66, 68, 70, 71, 720
For data set A, the mean and median are 68.
For data set B:
Formula:
[tex]Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}[/tex]
[tex]Mean =\displaystyle\frac{1124}{7} = 160.57[/tex]
[tex]Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}[/tex]
Sorted data:
64, 65, 66, 68, 70, 71, 720
[tex]\text{Median} = \dfrac{7+1}{2}^{th} \text{ term} = 4^th\text{ term} = 68[/tex]
Clearly, 720 is the is a outlier.
As seen mean is affected a lot by the change in the last observation as the median remains the same.
The measure that will be affected by this last observation in dataset B is mean
Given:
Dataset A: 64 65 66 68 70 71 72
Dataset B: 64 65 66 68 70 71 720
- The mean and median of dataset A are 68
How to find mean and median
Mean of dataset B = (64 + 65 + 66 + 68 + 70 + 71 + 720) / 7
= 1,124 /7
= 160.571428571428
- Median = 68
Therefore, measure that will be affected by this last observation in dataset B is mean
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