Answer:
3.6512 rad/s
37.97248 m/s
6.7808 m/s²
138.645118976 m/s²
Explanation:
r = Radius of centrifuge = 10.4 m
[tex]\phi=0.326t^2[/tex]
Differentiating with respect to time
[tex]\omega=\dfrac{d\phi}{dt}\\\Rightarrow \omega=\dfrac{d}{dt}0.326t^2\\\Rightarrow \omega=0.652t[/tex]
At t = 5.6 s
[tex]\omega=0.652\times 5.6\\\Rightarrow \omega=3.6512\ rad/s[/tex]
Angular speed is 3.6512 rad/s
Tangential speed is given by
[tex]v=r\omega\\\Rightarrow v=10.4\times 3.6512\\\Rightarrow v=37.97248\ m/s[/tex]
The tangential speed is 37.97248 m/s
Angular acceleration is given by
[tex]\alpha=\dfrac{d\omega}{dt}\\\Rightarrow \alpha=0.652\ rad/s^2[/tex]
Tangential acceleration is given by
[tex]a_t=\alpha r\\\Rightarrow a_t=0.652\times 10.4\\\Rightarrow a_t=6.7808\ m/s^2[/tex]
The tangential acceleration is 6.7808 m/s²
Radial acceleration is given by
[tex]a_r=\dfrac{v^2}{r}\\\Rightarrow a_r=\dfrac{37.97248^2}{10.4}\\\Rightarrow a_r=138.645118976\ m/s^2[/tex]
The radial acceleration is 138.645118976 m/s²