Respuesta :
Answer: a. 242.5 pounds
b. 236 pounds
c . 208 and 278 pounds
The results are unlikely to be representative of all players in that sport's league because players randomly selected from championship sports team not the whole league.
Step-by-step explanation:
Given : Listed below are the weights in pounds of 11 players randomly selected from the roster of a championship sports team.
278 303 186 292 276 205 208 236 278 198 208
Mean = [tex]\dfrac{\text{Sum of weights of all players}}{\text{Number of players}}[/tex]
[tex]=\dfrac{278+303+186+292+276+205+208+236+278+198+208}{11}\\\\=\dfrac{2668}{11}\approx242.5\text{ pounds}[/tex]
For median , first arrange weights in order
186, 198 , 205 , 208, 208 , 236 , 276 , 278 ,278, 292 , 303
Since , number of data values is 11 (odd)
So Median = Middlemost value = 236 pounds
Mode = Most repeated value= 208 and 278
The results are unlikely to be representative of all players in that sport's league because players randomly selected from championship sports team not the whole league.
The mean, median and mode values of the distribution are :
- 242.5, 236 and (208 and 278) respectively.
Given the data :
- 278, 303, 186, 292, 276, 205, 208, 236, 278, 198, 208
Arrange the data in ascending order :
- 186, 198, 205, 208, 208, 236, 276, 278, 278, 292, 303
The mean = ΣX/ n
- Where, n = sample size = 11
- Mean = (186 + 198 + 205 + 208 + 208 + 236 + 276 + 278 + 278 + 292 + 303) / 11
- Mean = 2668 / 11
- Mean = 242.545
The median ;
- Since the data has been arranged :
- 1/2(n + 1)th
- 1/2(11 + 1)th = 1/2(12)th = 6th value
- The 6th value in the ordered data is 236
- Hence, the median = 236
The mode :
- The mode of the distribution is the most frequently occurring value :
- The most frequently occurring values are : 208 and 278 with frequency values of 2.
Therefore ;
Mean = 242.5 pounds
Median = 236 pounds
Mode = 208 and 278
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