A random sample of 11 days were selected from last year's records maintained by the maternity ward in a local hospital, and the number of babies born each day of the days is given below: 3 7710 0 712 530 Find the five number summary (minimum, first quartile, second quartile, third quartile, maximum) of the data.

Respuesta :

Answer: ( Min = 0 , [tex]Q_1=1[/tex] , [tex]Q_2=3[/tex] , [tex]Q_3=7[/tex] , Max = 10 )

Step-by-step explanation:

Given : A random sample of 11 days were selected from last year's records maintained by the maternity ward in a local hospital, and the number of babies born each day of the days is given below:

3  7   7   10    0    7    1    2    5   3    0

We first arrange them in increasing order , we get

0    0    1    2   3   3   5     7   7   7   10

Here , N= 11

Now , we can see that

Minimum value = 0

Maximum value = 10

First quartile [tex]Q_1[/tex]= [tex](\dfrac{N+1}{4})^{th}\ term=(\dfrac{12}{4})^{th}\ term = 3^{rd} term =1[/tex]

Second quartile [tex]Q_2[/tex]= Median = Middlemost number = 3

Third quartile [tex]Q_3[/tex] =  [tex](\dfrac{3(N+1)}{4})^{th}\ term=(\dfrac{36}{4})^{th}\ term[/tex]

[tex]= 9^{th} term =7[/tex]

∴ The required five number summary : ( Min = 0 , [tex]Q_1=1[/tex] , [tex]Q_2=3[/tex] , [tex]Q_3=7[/tex] , Max = 10 )

ACCESS MORE
EDU ACCESS
Universidad de Mexico