Answer: ( Min = 0 , [tex]Q_1=1[/tex] , [tex]Q_2=3[/tex] , [tex]Q_3=7[/tex] , Max = 10 )
Step-by-step explanation:
Given : A random sample of 11 days were selected from last year's records maintained by the maternity ward in a local hospital, and the number of babies born each day of the days is given below:
3 7 7 10 0 7 1 2 5 3 0
We first arrange them in increasing order , we get
0 0 1 2 3 3 5 7 7 7 10
Here , N= 11
Now , we can see that
Minimum value = 0
Maximum value = 10
First quartile [tex]Q_1[/tex]= [tex](\dfrac{N+1}{4})^{th}\ term=(\dfrac{12}{4})^{th}\ term = 3^{rd} term =1[/tex]
Second quartile [tex]Q_2[/tex]= Median = Middlemost number = 3
Third quartile [tex]Q_3[/tex] = [tex](\dfrac{3(N+1)}{4})^{th}\ term=(\dfrac{36}{4})^{th}\ term[/tex]
[tex]= 9^{th} term =7[/tex]
∴ The required five number summary : ( Min = 0 , [tex]Q_1=1[/tex] , [tex]Q_2=3[/tex] , [tex]Q_3=7[/tex] , Max = 10 )