Question

Write a function rule for the area of a rectangle whose length is 7 ft more than its width. What is the area of the rectangle when it’s width is 8ft?

Answer 1

Answer:

$A = w^2 + 7w$   is the rule for the area of a rectangle.

A = 120 sq ft, when it’s width is 8 ft.

Step-by-step explanation:

Here, let us assume the width of the rectangle =  w

So, the length here = Width +  7 ft = (w +  7) ft

Now, AREA of a RECTANGLE = Length x Width

Substituting here the values of length and width, we get:

A = (w) x (w +  7) $= w^2 + 7 w$

$\implies A = w^2 + 7w$

The above function is the rule for the area of a rectangle.

Given: w = 8  ft

To find the area: put w  = 8 in $A = w^2 + 7w$

We get: A  = 8²  +  7(8)  

                 = 64 +  56  = 120

or, A  = 120 sq ft.

Hence, area = 120 sq ft, when it’s width is 8 ft.