Respuesta :
Answer:
- Option (b) 6, 24, 96, 384
Explanation:
The complete question is:
A sequence can be generated by using [tex]a_n=4a_{(n-1)}[/tex] where [tex]a_1=6[/tex] and n is a whole number greater than 1. What are the first four terms in the sequence.
The given rule [tex]a_n=4a_{(n-1)}[/tex] is a recursive formula, which means that to find any term consecutive term, from the second one, you multiply the current term by 4.
Thus:
[tex]a_1=6\\ \\ a_2=4a_1=4\times 6=24\\\\ a_3=4a_2=4\times 24=96\\ \\ a_4=4a_3=4\times 96=384[/tex]
Answer:
The option (b) is correct as the sequence is generated as 6, 24, 94, 384,...
Step-by-step explanation:
Considering the sequence
[tex]a_{n} =4a_{n-1}[/tex]
As [tex]a_{1} =6[/tex]
So,
[tex]a_{n} =4a_{n-1}[/tex]
[tex]a_{2} =4a_{2-1}[/tex]
[tex]a_{2} =4a_{1}[/tex]
[tex]a_{2} =4.6[/tex]
[tex]a_{2} =24[/tex]
[tex]a_{3} =4a_{3-1}[/tex]
[tex]a_{3} =4a_{2}[/tex]
[tex]a_{3} =4.24[/tex]
[tex]a_{3} =96[/tex]
[tex]a_{4} =4a_{4-1}[/tex]
[tex]a_{4} =4a_{3}[/tex]
[tex]a_{4} =4a_{3}[/tex]
[tex]a_{4} =4.96[/tex]
[tex]a_{4} =384[/tex]
Therefore, the option (b) is correct as the sequence is generated as 6, 24, 94, 384,...
Keywords: sequence
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