Answer:
Emil's back pack weigh now [tex]5\frac{1}{8}\ pounds[/tex].
Step-by-step explanation:
Given:
Total Weight of backpack = [tex]6\frac{3}{8}\ pounds[/tex]
[tex]6\frac{3}{8}\ pounds[/tex] can be Rewritten as [tex]\frac{51}{8}\ pounds[/tex]
Weight of backpack = [tex]\frac{51}{8}\ pounds[/tex]
Weight of Book 1 = [tex]\frac{3}{4}\ pound[/tex]
Weight of Book 2 = [tex]\frac{1}{2}\ pound[/tex]
We need to find weight of back pack after removing books.
Solution:
Now we can say that;
weight of back pack after removing books can be calculated by Subtracting Weight of Book 1 and Weight of Book 2 from Total Weight of backpack.
framing in equation form we get;
weight of back pack after removing books = [tex]\frac{51}{8}-\frac{3}{4}-\frac{1}{2}[/tex]
Now to solve the equation we will first make the denominator common using LCM.
weight of back pack after removing books =[tex]\frac{51\times1}{8\times1}-\frac{3\times2}{4\times2}-\frac{1\times4}{2\times4}=\frac{51}{8}-\frac{6}{8}-\frac{4}{8}[/tex]
Now the denominators are common so we will solve the numerator.
weight of back pack after removing books = [tex]\frac{51-6-4}{8}=\frac{41}{8}\ pounds \ \ OR \ \ 5\frac{1}{8}\ pounds[/tex]
Hence Emil's back pack weigh now [tex]5\frac{1}{8}\ pounds[/tex].
