Question

At 20°C, the resistance of a sample of nickel is 525 Ω. What is the resistance when the sample is heated to 70°C? Let α = 0.005866 at 20°C. Explain please.

Answer 1

The final resistance is $679\Omega$

Explanation:

The relationship between the resistance of a metal and the temperature is

$R(T) = R_0(1+\alpha (T-T_0))$

where

$R_0$ is the resistance at a temperature of $T_0$

R is the resistance at temperature T

$\alpha$ is the temperature coefficient of resistance

In this problem, we have:

$R_0 = 525 \Omega$

$T_0 = 20^{\circ}C$

$\alpha = 0.005866 \Omega/^{\circ}C$

Therefore, the resistance when $T=70^{\circ}C$ is

$R=(525)(1+0.005866(70-20))=679\Omega$

Learn more about resistance:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

Answer 2

Answer:

Therefore the new resistance would be 679 Ω

Explanation:

Resistance is the opposition to the flow of electric current. The resistance of an object given its coefficient of resistance can be obtained with the expression bellow;

R =R_ref [1+ α (T - T_ref)]

Where R is the new resistance

R_ref is the base resistance = 525 Ω

α is the coefficient of resistance at  20°C = 5

T is the new temperature = 70°C

T_ref is the base temperature =  20°C

Substituting the values into the equation we have;

R = 525 x  [ 1 + 0.005866 (70-20)]

R =  525 x  [ 1 + 0.005866 (50)]

R = 525 x 1.2933

R = 678.98

R≈ 679 Ω

Therefore the new resistance is 679 Ω