Question

The polynomial 8x+9+3x^6−4x^3, when rewritten in descending order, using a coefficient or a constant of 0 for any missing terms is _[blank 1]_ + _[blank 2]_ + _[blank 3]_ + _[blank 4]_ + _[blank 5]_ + _[blank 6]_ + _[blank 7]_.

Answer 1

Answer:

The given polynomial can be rewritten as in descending order is

$3x^6+0x^5+0x^4-4x^3+0x^2+8x+9$

Step-by-step explanation:

Given polynomial expression is $8x+9+3x^6-4x^3$

To rewrite the given polynomial in descending order as below :

$8x+9+3x^6-4x^3$

Rewritting the above polynomial in descending order and using a coefficient or a constant of 0 for any missing terms as below :

The given polynomial becomes

$3x^6+0x^5+0x^4-4x^3+0x^2+8x+9$

Therefore the given polynomial can be rewritten as in descending order is

$3x^6+0x^5+0x^4-4x^3+0x^2+8x+9$