Question

simplifying inside parentheses first pt. 2

Answer 1

Answer:

The answer to your question is the second option

Step-by-step explanation:

Process

Simplify using exponents laws, first inside the parentheses and then outside the parentheses.

                             $[\frac{a^{-2}b^{2}}{a^{2}b^{-1}} ]^{-3}$

a) Simplify a

                        a⁻² a⁻² = a⁻⁴

b) Simplify b

                        b² b¹ = b³

c) Write the result

                        $[\frac{b^{3}}{a^{4}}]^{-3}$

d)                      $[\frac{a^{4}}{b^{3}}]^{3}$

e) Simplify

                       $\frac{(a^{4})^{3}}{(b^{3})3}$

f) Result

                      $\frac{a^{12}}{b^{9}}$