Question

Assume this field is generated by a point charge of Q = 5 × 10-9 C. How far away is this charge located? Give your answer in meters.

Answer 1

E=Eq,

where F is the electrostatic force (or Coulomb force) exerted on a positive test charge q.

Answer 2

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A charged particle (q = 7.5 × 10-10 C) experiences a force of F in an electric field. Assume this field is generated by a point charge of Q = 5 ×$10-9$ C. How far away is this charge located? Give your answer in meters.

The distance of the charge is r = √44.95 * $10^{-18}$ / F

How to find the distance of a charged particle?

The magnitude of the electric field (E) produced by a point charge with a charge of magnitude Q, at a point a distance r away from the point charge, is given by the equation E = Qk/r², where k is a constant with a value of 8.99 x$10^{-9}$N m²/C².

E = F q = k* Q / r²

r² =  k*Q/ E

r² = 8.99 x $10^{-9}$ * 5 * $10-9$ / F

r = √44.95 * $10^{-18}$ / F

A charged particle also called an ion, is an atom with a positive or negative charge. This happens whenever something called an ionic bond forms. Two particles that have different numbers of electrons (the smallest particle in an atom which is negative) start reacting to each other.

Learn more about charged particles here: brainly.com/question/18763828

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