Respuesta :
The question is incomplete, here is the complete question:
An aqueous solution at 25°C has a [tex]H_3O^+[/tex] concentration of [tex]8.8\times 10^{-12}M[/tex] . Calculate the [tex]OH^-[/tex] concentration. Be sure your answer has the correct number of significant digits.
Answer: The hydroxide ion concentration of the solution is [tex]0.1\times 10^{-2}M[/tex]
Explanation:
To calculate the pH of the solution, we use the equation:
[tex]pH=-\log[H_3O^+][/tex]
We are given:
[tex][H_3O^+]=8.8\times 10^{-12}M[/tex]
Putting values in above equation, we get:
[tex]pH=-\log (8.8\times 10^{-12})\\\\pH=11.05[/tex]
To calculate the hydroxide ion concentration, we first calculate pOH of the solution, which is:
pH + pOH = 14
[tex]pOH=14-11.05=2.95[/tex]
To calculate hydroxide ion concentration of the solution, we use the equation:
[tex]pOH=-\log[OH^-][/tex]
We are given:
pOH = 2.95
Putting values in above equation, we get:
[tex]2.95=-\log[OH^-][/tex]
[tex][OH^-]=10^{-2.95}[/tex]
[tex][OH^-]=1.12\times 10^{-3}M=0.1\times 10^{-2}M[/tex]
Hence, the hydroxide ion concentration of the solution is [tex]0.1\times 10^{-2}M[/tex]
