Question

what are the solutions of 2x^2-6+5=0 ?

Answer 1

$

2x^2-6+5=0 \\

2x^2-1=0 \\

2x^2=1 \\

x^2=\frac{1}{2} \\

x=\pm\frac{1}{\sqrt{2}}

$

You may also want to rationalise the denominator, to do so multiply fraction by $\sqrt{2}$ to get $x=\pm\frac{\sqrt{2}}{2}$.

Hope this helps.