Question

what are the solutions of 3 x^2-x+4=0

Answer 1

Answer:

The solution of given equation for x is  (0.16 + i 1.14) , (0.16 - i 1.14)  

Step-by-step explanation:

Given as :

The quadratic equation is as 3 x² - x + 4 = 0

Since The given equation is quadratic

∵, Standard quadratic equation is ax² + bx + c = 0

Now, x = $\frac{-b\pm \sqrt{b^{2} - 4\times a\times c}}{2\times a}$

Comparing the equation

i.e x = $\frac{-(-1)\pm \sqrt{(-1)^{2} - 4\times 3\times 4}}{2\times 3}$

or, x = $\dfrac{1\pm \sqrt{(1-48)}}{6}$

Or, x = $\dfrac{1\pm \sqrt{(-47)}}{6}$

Or, x = $\dfrac{1\pm i6.85}{6}$

Or, x = (0.16 + i 1.14)   , (0.16 - i 1.14)

So, The solution of given equation for x = (0.16 + i 1.14)   , (0.16 - i 1.14)

Hence, The solution of given equation for x is  (0.16 + i 1.14) , (0.16 - i 1.14)  . Answer