Question

A 0.2 kg ball moving east at 6 m/s hits a wall and bounces off to the west at 4 m/s. What is the magnitude of the change in momentum of the ball? choices are below
2 kg m/s
0.8 kg m/s
0.4 kg m/s
1.2 kg m/s

Answer 1

The change in momentum is (magnitude) 2 kg m/s

Explanation:

The change in momentum of an object is given by

$\Delta p = m(v-u)$

where

m is the mass of the object

v is the final velocity

u is the initial velocity

Since momentum is a vector, it is important to correctly take into account the sign (therefore, the direction) of the velocities.

For the ball in this problem, we have:

m = 0.2 kg is the mass

u = 6 m/s (taking east as positive direction)

v = -4 m/s (west is negative direction)

So the change in momentum is

$\Delta p = (0.2)(-4-(6))=-2 kg m/s$

And since we are only interested in the magnitude, the answer is

$2 kg m/s$

Learn more about change in momentum:

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