Juan and raj cut up a banana to put on cereal. juan puts 1/7 of the banana on his bowl of cereal, and raj puts 2/5 of the banana on his bowl of cereal.
what fraction of the banana did juan and raj put on their cereal altogether?
a. 2/35 banana
b. 3/12 banana
c. 3/7 banana
d. 19/35 banana
Juan and Raj altogether put 19/35 banana
Given that, Juan and Raj cut up a banana to put on cereal
[tex]fraction\ of\ banana\ put\ by\ Juan = \frac{1}{7}\\\\fraction\ of\ banana\ put\ by\ Raj = \frac{2}{5}[/tex]
We have to find the fraction of banana put by Juan and Raj altogether
This means, we have to add both the fractions
[tex]fraction\ of\ banana\ put\ altogether = fraction\ of\ banana\ put\ by\ Juan + fraction\ of\ banana\ put\ by\ Raj[/tex]
[tex]fraction\ of\ banana\ put\ altogether = \frac{1}{7} + \frac{2}{5}\\\\\text{Cross multiply to simplify }\\\\fraction\ of\ banana\ put\ altogether = \frac{1 \times 5 + 2 \times 7}{7 \times 5}\\\\fraction\ of\ banana\ put\ altogether = \frac{5+14}{35}\\\\fraction\ of\ banana\ put\ altogether = \frac{19}{35}[/tex]
Thus they put [tex]\frac{19}{35}[/tex] of banana by Juan and Raj altogether