Answer:
Option A) is correct.
Step-by-step explanation:
We need to use normalcdf command to find the probability that the variable would fall into a certain interval that we would supply.
As
and
And we have to determine the percent of students have scored more than 75 points.
So,
Mean = μ = 60
Standard Deviation = σ = 5
As we have to determine the percent of students have scored more than 75 points.
Hence,
normalcdf(75,100,60,5) = .0013
Converting on percentage → .0013 × 100 = 0.1
Therefore, option A) is correct as 0.1 percent of students have scored more than 75 points.
Keywords: distribution, mean, median
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