Question

a child sleds down a steep snow-covered hill with an acceleration of 3.94 m/s^2. if her initial speed is 0.0m/s and her final speed is 21.1 m/s, how long does it take for her to travel from the top of the hill to the bottom?

Answer 1

The time taken is 5.36 s

Explanation:

The motion of the child is a uniformly accelerated motion, therefore we can use the following suvat equation:

$v=u+at$

where

a is the acceleration

u is the initial  velocity

v is the final velocity

t is the time

For the child in this problem, we have:

u = 0

v = 21.1 m/s

$a=3.94 m/s^2$

Substituting and solving  for t,  we find the time taken:

$t=\frac{v-u}{a}=\frac{21.1-0}{3.94}=5.36 s$

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