Question

Deangelo needs 100 lb of garden soil to landscape a building. And the company's storage area, he finds two cases holding 24 and 2/3 lb of garden soil each,and a third case holding 19 3/8 lb. How much garden soil does D'Angelo still need in order to do the job?

Answer 1

Question is not proper; Proper question is given below;

D'Angelo needs 100 lb of garden soil to landscape a building. In the company’s storage area, he finds 2 cases holding 24 3/4 lb of garden soil each, and a third case holding 19 3/8 lb. How much gardening soil does D'Angelo still need in order to do the job?

Answer:

D'Angelo required $31 \frac{1}{8}\ lb$ more garden soil to do the job.

Step-by-step explanation:

Given:

Total Amount of garden soil needed to do job = 100 lb

Amount of garden soil in 1st case = $24\frac{3}{4}\ lb$

$24\frac{3}{4}\ lb$ can be rewritten as $\frac{99}{4}\ lb$

Amount of garden soil in 1st case =  $\frac{99}{4}\ lb$

Amount of garden soil in 2nd case = $24\frac{3}{4}\ lb$

$24\frac{3}{4}\ lb$ can be rewritten as $\frac{99}{4}\ lb$

Amount of garden soil in 2nd case =  $\frac{99}{4}\ lb$

Amount of garden soil in 3rd case = $19\frac{3}{8}\ lb$

$19\frac{3}{8}\ lb$ can be rewritten as $\frac{155}{8}\ lb$

Amount of garden soil in 3rd case =  $\frac{155}{8}\ lb$

We need to find Amount of garden soil required more.

Solution:

Now we can say that;

Amount of garden soil required more can be calculated by subtracting sum of Amount of garden soil in 1st case and Amount of garden soil in 2nd case  and Amount of garden soil in 3rd case from Total Amount of garden soil needed to do job.

framing in equation form we get;

Amount of garden soil required more = $100-\frac{99}{4}-\frac{99}{4}-\frac{155}{8}$

To solve the fraction we will make the denominator common using LCM.

Amount of garden soil required more = $\frac{100\times8}{8}-\frac{99\times2}{4\times2}-\frac{99\times2}{4\times2}-\frac{155\times1}{8\times1}= \frac{800}{8}-\frac{198}{8}-\frac{198}{8}-\frac{155}{8}$

Now denominators are common so we will solve the numerator.

Amount of garden soil required more = $\frac{800-198-198-155}{8}=\frac{249}{8}\ lb \ \ OR \ \ 31 \frac{1}{8}\ lb$

Hence D'Angelo required $31 \frac{1}{8}\ lb$ more garden soil to do the job.