Answer:
Please check below the step-by-step explanation.
Step-by-step explanation:
Considering the quadratic expression
[tex]ax^2+bx\:+\:c\:=0[/tex]
[tex]a,\:b,\:and\:c\:can\:have\:any\:value,\:except\:that\:a\:can't\:be\:0.[/tex]
[tex]To\:Factorise\:a\:Quadratic\:is\:to:[/tex]
" [tex]find\:what\:to\:multiply\:to\:get\:the\:Quadratic[/tex] "
For example, multiplying [tex](x + 3)[/tex] and [tex](x - 2)[/tex] together will bring [tex]x^2+x-6[/tex]
i.e.
[tex]\left(x+3\right)\left(x-2\right) = xx+x\left(-2\right)+3x+3\left(-2\right)[/tex]
[tex]\mathrm{Apply\:minus-plus\:rules}[/tex]
[tex]+\left(-a\right)=-a[/tex]
[tex]\left(x+3\right)\left(x-2\right) = xx-2x+3x-3\cdot \:2[/tex]
[tex]= x^2+x-6[/tex]
Therefore, [tex](x + 3)[/tex] and [tex](x - 2)[/tex] are factors of [tex]x^2+x-6[/tex]
Keywords: factorize, quadratic expression
Learn more about quadratic expression from brainly.com/question/12182022
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