Answer:
The x-coordinate of the point of intersection is -2
Step-by-step explanation:
Here we have a typical system of linear equations whose solution will give us both the x- and the y- coordinates (i.e. the intersection point).
Let us solve the system and find which matches the available options, as follow. Given:
[tex]2x+y=1\\9x+3y=-3[/tex]
Taking the first expression and re arranging to solve for [tex]x[/tex] we have:
[tex]2x+y=1\\2x=1-y\\x=\frac{1-y}{2}[/tex] Eqn.(1)
Plugging in it, in the second expression we then have
[tex]9(\frac{1-y}{2} )+3y=-3\\\\\frac{9}{2}-\frac{9y}{2}+3y=-3\\ \\\frac{9}{2}-\frac{9y}{2}+\frac{6y}{2}=-\frac{6}{2}\\ \\-\frac{9y}{2}+\frac{6y}{2}=-\frac{6}{2}-\frac{9}{2}\\-3y=-15\\y=\frac{-15}{-3}\\ y=5[/tex]
So finally plugging in the y value in Eqn.(1) we have
[tex]x=\frac{1-5}{2} \\x=\frac{-4}{2}\\ x=-2[/tex]
The x-coordinate of the point of intersection is -2