Question

3000 N is exerted for 4.0 seconds on a 9500 kg object a) What is the impulse impacted on the object

Answer 1

Answer: 12000 kg m/s

Explanation:

According to the Impulse-Momentum Theorem, we have:

$F \Delta t= \Delta p$

Where:

$F=3000 N$ is the exerted force

$\Delta t=4 s$ is the time interval

$\Delta p$ is the change in momentum or impulse

Then:

$(3000 N)(4 s)= \Delta p$

$\Delta p=12000 kg m/s$  This is the impulse impacted on the object