Answer:
Therefore, Equation of line and the slope is
[tex]y=-2x[/tex]
[tex]Slope = -2[/tex]
Step-by-step explanation:
Given:
Let,
point A( x₁ , y₁) ≡ ( 3 ,-6)
point B( x₂ , y₂ )≡ (-1 , 2)
To Find:
Equation of Line AB =? ( Assumption)
Solution:
Equation of a line passing through a points A( x₁ , y₁) and point B( x₂ , y₂ ) is given by the formula Two -Point Form,
[tex](y-y_{1})=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }\times (x-x_{1})[/tex]
Now on substituting the slope and point A( x₁ , y₁) ≡ ( 3 , 6) and B( x₂ , y₂ )≡ (-1 , 2) we get
[tex](y-(-6))=\dfrac{2--6}{-1-3}\times (x-3)\\\\y+6=\dfrac{8}{-4}(x-3)\\\\y+6=-2(x-3)\\y+6=-2x+6\\y=-2x[/tex] .....Required Equation of line
Which is also in the form of
[tex]y=mx[/tex] ....Also called as Equation of line Passing through Origin.
where , m =slope
Therefore, Equation of line and the slope is
[tex]y=-2x[/tex]
[tex]Slope = -2[/tex]