Respuesta :

Answer:

Therefore, Equation of line and the slope is

[tex]y=-2x[/tex]

[tex]Slope = -2[/tex]

Step-by-step explanation:

Given:  

Let,  

point A( x₁ , y₁) ≡ ( 3 ,-6)

point B( x₂ , y₂ )≡ (-1 , 2)

To Find:  

Equation of Line AB =? ( Assumption)

Solution:  

Equation of a line passing through a points A( x₁ , y₁) and point B( x₂ , y₂ ) is given by the formula Two -Point Form,  

[tex](y-y_{1})=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }\times (x-x_{1})[/tex]  

Now on substituting the slope and point A( x₁ , y₁) ≡ ( 3 , 6) and B( x₂ , y₂ )≡ (-1 , 2) we get  

[tex](y-(-6))=\dfrac{2--6}{-1-3}\times (x-3)\\\\y+6=\dfrac{8}{-4}(x-3)\\\\y+6=-2(x-3)\\y+6=-2x+6\\y=-2x[/tex] .....Required Equation of line

Which is also in the form of

[tex]y=mx[/tex] ....Also called as Equation of line Passing through Origin.

where , m =slope

Therefore, Equation of line and the slope is

[tex]y=-2x[/tex]

[tex]Slope = -2[/tex]

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