Answer:
The volume of radius is [tex]\frac{4}{3}[/tex] × π × radius³ Proved
Explanation:
Given as :
We know that volume of sphere is v = [tex]\frac{4}{3}[/tex] × π × radius³
Or, v = [tex]\frac{4}{3}[/tex] × π × r³
Let prove the volume of sphere
So, From the figure of sphere
At the height of z , there is shaded disk with radius x
Let Find the area of triangle with side x , z , r
From Pythagorean theorem
x² + z² = r²
Or, x² = r² - z²
Or, x = [tex]\sqrt{r^{2}-z^{2} }[/tex]
Now, Area of shaded disk = Area = π × x²
Where x is the radius of disk
Or, Area of shaded disk = π × ([tex]\sqrt{r^{2}-z^{2} }[/tex]) ²
∴ Area of shaded disk = π × (r² - z²)
Again
If we calculate the area of all horizontal disk, we can get the volume of sphere
So, we simply integrate the area of all disk from - r to + r
i.e volume = [tex]\int_{-r}^{r} \Pi(r^{2}-z^{2} )dz[/tex]
Or, v = [tex]\int_{-r}^{r} \Pi r^{2}dz[/tex] - [tex]\int_{-r}^{r} \Pi z^{2}dz[/tex]
Or, v = π r² (r + r) - π [tex]\frac{r^{3} -(-r)^{3})}{3}[/tex]
Or, v = π r² (r + r) - π [tex]\frac{2r^{3}}{3}[/tex]
Or, v = 2πr³ - π [tex]\frac{2r^{3}}{3}[/tex]
Or, v = 2πr³ ([tex]\frac{3-1}{3}[/tex])
Or, v = 2πr³ × [tex]\frac{2}{3}[/tex]
∴ v = [tex]\frac{4}{3}[/tex] × π × r³
Hence, The volume of radius is [tex]\frac{4}{3}[/tex] × π × radius³ Proved . Answer