Respuesta :
Answer:
the quantity of x squared plus 4x plus 43, all over 5 times the quantity of x plus 1
Step-by-step explanation:
we have
[tex]\frac{x+9}{x+1} +\frac{x-2}{5}[/tex]
Find the LCD
LCD=5(x+1)
[tex]\frac{5(x+9)+(x+1)(x-2)}{5(x+1)}[/tex]
[tex]\frac{5x+45+x^2-2x+x-2}{5(x+1)}[/tex]
[tex]\frac{5x+45+x^2-x-2}{5(x+1)}[/tex]
[tex]\frac{x^2+4x+43}{5(x+1)}[/tex]
therefore
the quantity of x squared plus 4x plus 43, all over 5 times the quantity of x plus 1