Answer:
Therefore the measur angle ACB
[tex]m\angle ACB=61.93\°[/tex]
Step-by-step explanation:
Given:
ΔABC is a right Triangle at ∠A = 90°
AB = 15 ....Side Opposite to ∠ACB
AC = 8 ....Side Adjacent to ∠ACB
To Find:
m∠ACB = ?
Solution:
In Right Angle Triangle ABC, Tangent Identity we have
[tex]\tan (\angle ACB) = \dfrac{\textrm{side opposite to angle ACB}}{\textrm{side adjacent to angle ACB}}[/tex]
Substituting the values we get
[tex]\tan (\angle ACB) = \dfrac{AB}{AC}=\dfrac{15}{8}=1.875\\\\\angle ACB=\tan^{-1}(1.875)\\m\angle ACB=61.93\°[/tex]
Therefore the measur angle ACB
[tex]m\angle ACB=61.93\°[/tex]
