Question

The end of Hubbard Glacier in Alaska advances by an average of 105 feet per year.

What is the speed of advance of the glacier in

m/s

?

Answer 1

Answer:

Speed of the glacier, $v=1.0148\times 10^{-6}\ m/s$

Explanation:

Given that,

The average speed of Hubbard Glacier, $v=105\ feet/year$

We need to find speed of advance of the glacier in  m/s. As we know that,

1 meter = 3.28 feet

And

$1\ year=3.154\times 10^7\ second$

Using the above conversions, we can write the value of average speed is :

$v=1.0148\times 10^{-6}\ m/s$

So, the speed of advance of the glacier is $1.0148\times 10^{-6}\ m/s$. Hence, this is the required solution.