Respuesta :

Answer:

0.4 mL is the volume of 122 g of Cupper (II) nitrate

Explanation:

You have to work with density, to solve the problem.

Density is the relation mass / volume

Cupper (II) nitrate density = Cupper (II) nitrate mass / Cupper (II) nitrate volume

3.05 g/mL = 122 g / Cupper (II) nitrate volume

Cupper (II) nitrate volume = 122 g / 3.05 g/mL

Cupper (II) nitrate volume = 0.4 mL

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