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21-01-2020
Chemistry

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A solution is made by mixing 135.g of chloroform CHCl3 and 141.g of acetyl bromide CH3COBr. Calculate the mole fraction of chloroform in this solution. Round your answer to 3 significant digits?

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Eduard22sly Eduard22sly

21-01-2020

Answer: the mole fraction for chloroform = 0.496

Explanation:Please see attachment for explanation

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