Question

If a speaker gives a sound intensity of 10^-6W/m^2 at a certain point, what is the sound intensity level beta at that point

Answer 1

Answer: 60dB

Explanation:

Sound intensity level β = 10log(I/Io)

Where Io= 10^−12 W/m2 is the reference intensity .

I= 10^-6W/m^2

β= 10log(10^-6/10^-12)

β= 10log(10^6)

β= 10×6 × log 10

Where log 10=1

β=60dB

Therefore, sound intensity level β is 60dB

Answer 2

The sound intensity level beta will be "60 dB".

Given:

• $l = 10^{-6} \ W/m^2$

As we know,

→ $Sound \ intensity \ level \ \beta = 10 log(\frac{l}{l_o} )$

Now,

→ $\beta = 10 log(\frac{10^{-6}}{10^{-12}} )$

      $= 10 log (10^6)$

      $= 10\times 6\times log 10$

We know, log 10 = 1

      $= 60 \ dB$

Thus the above approach is right.

Learn more:

https://brainly.com/question/2868845