the vertex of this parabola is at (-5, -2). When the x-value is -4, the y-value is 2. What is the coefficient of the squared expression in the parabola's equation?
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The coefficient of the squared expression in the parabola's equation is 4.
Solution:
Given data:
Vertex of the parabola = (–5, –2), x = –4, y = 2
Vertex = (h, k)
Therefore, h = –5 and k = –2
Verex form of the parabola is [tex]y=a(x-h)^2+k[/tex] – – – – (1)
Substitute the value of x, y, h and k in equation in (1).
[tex]2=a(-4-(-5))^2+(-2)[/tex]
⇒ [tex]2=a(-4+5)^2-2[/tex]
⇒ [tex]2+2=a(1)^2[/tex]
⇒ [tex]4=a[/tex]
Substitute a = 4 in equation (1), we get
[tex]y=4(x-h)^2+k[/tex]
Hence the coefficient of the squared expression in the parabola's equation is 4.