Question

Can somebody give me a equation for this word problem? Mateo drives six and three fifths miles to work, and Jennifer walks one and one fourth miles to work. How much does farther does Mateo travel to work than Jennifer?

Answer 1

Answer:

Mateo travels $5\frac{7}{20} \ miles$ (five and seven twentieth miles) more than Jennifer.

Step-by-step explanation:

Given:

Mateo drives six and three fifths miles to work,

Distance travel by Mateo = $6\frac{3}{5}\ miles$

$6\frac{3}{5}$ can be rewritten as $\frac{33}{5}$

Distance travel by Mateo =  $\frac{33}{5}$ miles.

Also Given:

Jennifer walks one and one fourth miles to work.

Distance travel by Jennifer = $1\frac{1}{4} \ miles$

$1\frac{1}{4}$ can be rewritten as $\frac{5}{4}$

Distance travel by Jennifer =  $\frac{5}{4}$ miles.

We need to find the distance travel more by Mateo than Jennifer.

Solution:

Now we can say that;

distance travel more by Mateo than Jennifer can be calculated by Subtracting Distance travel by Jennifer from Distance travel by Mateo.

framing in equation form we get;

distance travel more = $\frac{33}{5}-\frac{5}{4}$

Now to solve the same we will make the denominator common using L.C.M we get;

distance travel more = $\frac{33\times4}{5\times4}-\frac{5\times5}{4\times5}= \frac{132}{20}-\frac{25}{20}$

Now the denominators are same so we will solve the numerator.

distance travel more =$\frac{132-25}{20} = \frac{107}{20}\ miles \ \ \ OR \ \ \ 5\frac{7}{20} \ miles$

Hence Mateo travels $5\frac{7}{20} \ miles$ (five and seven twentieth miles) more than Jennifer.