10th grade geometry question writing a proof.
thanks! :)
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The Δvzy has two angles equal (∠v= 45° and ∠y=45°) and the third angle ∠z= 90° is different. Hence, it is proved that Δvzy is an isosceles triangle.
Step-by-step explanation:
The sum of the angles in a Rectangle is 360°
The sum of the angles in a Triangle is 180°
Consider the given rectangle as VWXY,
Consider the given triangle as vzy,
step 1: The Rectangle measures ∠V=90°, ∠W=90°, ∠Y=90°, ∠X=90°
step 2: The diagonals of Rectangle bisects the angle 90° into 45° and 45°
step 3: At ∠V= 90°, the diagonal VZ bisects at 45°
step 4: At ∠Y= 90°, the diagonal YW bisects at 45°
Take the Triangle vzy,
where ∠v= 45° and ∠y= 45°, Since the sum of angles in a triangle is 180°
The z can be calculated by 45°+45°+∠z =180°
∠z= 180°-45°-45°
∠z= 90°
Isosceles Triangle: The word "iso" means "Two". A triangle is said to be an isosceles triangle if the two angles of a triangle are equal or similar in value.
From the above steps,
It is proved that the Δvzy has two angles equal (∠v= 45° and ∠y=45°) and the third angle ∠z= 90° is different.
Hence proved Δvzy is an isosceles triangle.