Answer: The average velocity of the object over the time interval [3,6] is 20.
Step-by-step explanation:
Since we have given that
s(3) = 156
s(6) = 216
We need to find the average velocity over the time interval [3,6].
So, average velocity becomes
[tex]\dfrac{s(t_1)-s(t_0)}{t_1-t_0}\\\\=\dfrac{s(6)-s(3)}{6-3}\\\\=\dfrac{216-156}{3}\\\\=\dfrac{60}{3}\\\\=20[/tex]
Hence, the average velocity of the object over the time interval [3,6] is 20.