Question

On the first
On the first of each month, Shelly runs a 5k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table:
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Jan 40.55 July 35.38
Feb 41.51 Aug 37.48
Mar 42.01 Sept 40.87
Apr 38.76 Oct 50.32
May 36.32 Nov 41.59

Answer 1

Answer:

0.93

Step-by-step explanation:

u have to add them all and divide by 12. then u add all of them but the outlier and divide by 11. then u subtract.

Answer 2

The difference between the mean of the data, including the outlier and excluding the outlier is 0.76(39.982-39.224).

What is Mean?

A mean is an arithmetic average of a set of observations. it is given by the formula,

Mean = (Sum of observations)/Number of observations

The complete data is,

Jan 40.55       July 35.38

Feb 41.51         Aug 37.48

Mar 42.01        Sept 40.87

Apr 38.76        Oct 48.32

May 36.32       Nov 41.59

June 34.28      Dec 42.71

The mean of all the data including the outlier is,

Mean including the outlier

= (40.55 + 35.38 + 41.51 + 37.48 + 42.01 + 40.87 + 38.76 + 48.32 + 36.32 + 41.59 + 34.28 + 42.17) / 12

= 39.982

Now, in the given data set the outlier is 48.32, therefore, the mean excluding the outlier is,

Mean excluding the outlier

= (40.55 + 35.38 + 41.51 + 37.48 + 42.01 + 40.87 + 38.76 + 36.32 + 41.59 + 34.28 + 42.17) / 11

= 39.224

Hence, the difference between the mean of the data, including the outlier and excluding the outlier is 0.76(39.982-39.224).

Learn more about Mean:

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