kimberlyvargas7686 kimberlyvargas7686
  • 21-01-2020
  • Physics
contestada

By what factor does the sound intensity increase if the sound intensity level increases from 60 db to 61 db?

Respuesta :

muneebrehman muneebrehman
  • 22-01-2020

Answer:

[tex]\frac{I_{2}}{I_{1}} = 10^{0.1}[/tex]

Explanation:

The sound intensity level β can be mathematically defined as

[tex]\beta(dB) = 10log_{10}(\frac{I}{I_{o} } )[/tex]

where [tex]I_{o}[/tex] is the reference intensity and is equal to [tex]10^{-12}[/tex] [tex]W/m^{2}[/tex].

Now,

[tex]\beta_{2} - \beta_{1} = 10 log\frac{I_{2} }{I_{o}} -  10 log\frac{I_{1} }{I_{o}}\\62-60= 10log(\frac{\frac{I_{2} }{I_{o} } }{\frac{I_{1} }{I_{o} } } )\\1=10log(\frac{I_{2} }{I_{1} } )\\\\\frac{I_{2} }{I_{1} }=10^{0.1}[/tex]

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