Question

5. In order for an F-18 fighter jet to take off from an aircraft carrier, it needs to reach a
speed of 73 m/s by quickly accelerating down a 90 m long runway. If an F-18 starts its
takeoff from rest, what acceleration does the fighter jet undergo during takeoff?

Answer 1

Answer:

a = 29.60 ms²

Explanation:

Given

V(f) = 73m/s

S = 90m

V(i) = 0m/s beacuse it takeoff from rest

a = ?

Formula

S = (V(f)² - V(i)²)/ 2 a

So, put the values

2a (90) = ( (73)² - (0)²)

180a  = 5329

a = 5329/180

a = 29.60 ms²