Question

According to the following reaction, how many grams of hydrogen peroxide (
H
2
O
2
) are necessary to form 0.182 moles oxygen gas?
hydrogen peroxide (
H
2
O
2
) (aq)
→
water (l) + oxygen (g)

Answer 1

Answer:

12.4 g

Explanation:

Let's consider the following balanced equation.

H₂O₂(aq) → H₂O(l) + 0.5 O₂(g)

The molar ratio of H₂O₂ to O₂ is 1:0.5. The moles of H₂O₂ required to form 0.182 moles of O₂ are:

0.182 mol O₂ × (1 mol H₂O₂/ 0.5 mol O₂) = 0.364 mol H₂O₂

The molar mass of H₂O₂ is 34.01 g/mol. The mass of H₂O₂ corresponding to 0.364 moles is:

0.364 mol × 34.01 g/mol = 12.4 g