Question

Margaret and Kevin each improved their yards by planting rose bushes and daylilies. They bought their supplies from the same store. Margaret spent $74 on 7 rose bushes and 6 daylilies. Kevin spent $24 on 7 rose bushes and 1 daylily. Find the cost of one rose bush and one daylily

Answer 1

The cost of one rose bush is $2 and one day lily is $10.

Step-by-step explanation:

Let,

Cost of one rose bush = x

Cost of one day lily = y

According to given statement;

7x+6y=74       Eqn 1

7x+y=24         Eqn 2

Subtracting Eqn 2 from Eqn 1

$(7x+6y)-(7x+y)=74-24\\7x+6y-7x-y=50\\5y=50$

Dividing both sides by 5

$\frac{5y}{5}=\frac{50}{5}\\y=10$

Putting y=10 in Eqn 1

$7x+6(10)=74\\7x+60=74\\7x=74-60\\7x=14$

Dividing both sides by 7

$\frac{7x}{7}=\frac{14}{7}\\x=2$

The cost of one rose bush is $2 and one day lily is $10.

Keywords: linear equation, elimination method

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