Question

The FoxP2 gene is thought to be involved in language in humans. At prophase I, how many copies of the FoxP2 gene are present in a cell? Keep in mind that humans are diploid. 4 copies; 1 on each sister chromatid in a pair of homologous chromosomes 2 copies; 1 on each homologous chromosome 8 copies; 1 on each strand of each chromatid per homologous pair 8 copies; 1 on each sister chromatid in a pair of homologous chromosomes

Answer 1

Answer:

Four copies, one on each sister chromatid in a pair of homologous chromosomes.

Explanation:

FoxP2 gene is involved in speech and development of an individual. FoxP2 gene encodes the FoxP2 protein and plays an important role in the process of communication.

The gene is diploid and contain two copies of each chromosome. At the prophase I, the four copies of the FOXP2 gene is present in the cell. The two chromosome contains four chormatids. All these four chromatids present the copy of a chromosome.

Thus, the correct answer is option (1).

Answer 2

At prophase I, four (4) copies of the FoxP2 gene, one (1) on each sister chromatid in a pair of homologous, are present in a cell.

• Meiosis is a type of reductional cell division by which a cell duplicates its genetic material (DNA) and then divides twice to produce four daughter cells having half of the genetic material.

• Meiosis can be divided into two cell divisions called Meiosis I and Meiosis II.

• Before Prophase I (Meiosis I), the genetic material of a diploid (2n) cell is duplicated, thereby the parental cell contains at this stage of cell division four chromatids in a pair of homologous chromosomes.

• Each sister chromatid contains one gene locus where the FoxP2 gene can be mapped.

In conclusion, at prophase I, four (4) copies of the FoxP2 gene, one (1) on each sister chromatid in a pair of homologous, are present in a cell.

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