Answer:
Explanation:
given,
Light wave wavelength in Air, λ_(vac) = 670 nm
wavelength in transparent solid, λ= 420 nm
Refractive index of the solid
[tex]n = \dfrac{\lambda_{vac}}{\lambda}[/tex]
[tex]n = \dfrac{670}{420}[/tex]
n = 1.6
a) speed of light in the solid
[tex]v = \dfrac{c}{n}[/tex]
[tex]v = \dfrac{c}{1.6}[/tex]
v = 0.625 c
b) light's frequency in the solid
[tex]f = \dfrac{c}{\lambda_{vac}}[/tex]
frequency of light remain same when light move from one medium to another.
f is the frequency of light
[tex]f = \dfrac{3\times 10^8}{670\times 10^{-9}}[/tex]
f = 4.47 x 10⁻¹⁴ Hz
the light's frequency in the solid is equal to 4.47 x 10⁻¹⁴ Hz