Answer:
The lines are parallel with an acute angle of 0 degrees.
Missing Information:
The equations of lines are missing which are as follows:
Line 1:
x = 1 - 2t , y = 8 + t, z = 5
Line 2:
x = 2 + 4s , y = -1 -2s, z = 3
Step-by-step explanation:
First, we need to find the direction vectors of both the line, we can write them as:
Direction Vector of line 1 =[tex]D_{1}[/tex]= -2u + 1v + 0w
Direction Vector of line 2= [tex]D_{2}[/tex]=4u -2v+0w
As we can see,
[tex]D_{2}[/tex]=-2 [tex]D_{1}[/tex]
such that:
4u -2v+0w= -2(-2u + 1v + 0w)
Since,
[tex]D_{2}[/tex]=-2 [tex]D_{1}[/tex]
So the lines are parallel such that θ= 0 degrees. (Which is the acute angle between them)
All the points on line 1 have z-coordinate as 5 (z=5),
All the points on line 2 have z-coordinate as 3 (z=3),
Since the z-coordinate do not match , so the lines are not coincident.
Also as the lines are parallel so they are not intersecting.